Hard
Maximum Number of Intersections on the Chart — Python
Full explanation · Time O(nlogn) · Space O(n)
# Time: O(nlogn)
# Space: O(n)
# sort, line sweep, coordinate compression
class Solution(object):
def maxIntersectionCount(self, y):
"""
:type y: List[int]
:rtype: int
"""
val_to_idx = {x:i for i, x in enumerate(sorted(set(y)))}
cnts = [0]*(2*len(val_to_idx)+1)
for i in xrange(len(y)-1):
# [y[i], y[i+1]) <=> [y[i], y[i+1]-0.5] <=> [2*y[i], 2*y[i+1]-1]
left, right = 2*val_to_idx[y[i]], 2*val_to_idx[y[i+1]]+(-1 if y[i] < y[i+1] else +1)
cnts[min(left, right)] += 1
cnts[max(left, right)+1] -= 1
# [y[i], y[i]] <=> [2*y[i], 2*y[i]]
cnts[2*val_to_idx[y[-1]]] += 1
cnts[2*val_to_idx[y[-1]]+1] -= 1
result = cnt = 0
for c in cnts:
cnt += c
result = max(result, cnt)
return result
# Time: O(nlogn)
# Space: O(n)
# sort, line sweep
class Solution2(object):
def maxIntersectionCount(self, y):
"""
:type y: List[int]
:rtype: int
"""
events = []
for i in xrange(len(y)-1):
# [y[i], y[i+1]) <=> [y[i], y[i+1]-0.5] <=> [2*y[i], 2*y[i+1]-1]
left, right = 2*y[i], 2*y[i+1]+(-1 if y[i] < y[i+1] else +1)
events.append((min(left, right), +1))
events.append((max(left, right)+1, -1))
# [y[i], y[i]] <=> [2*y[i], 2*y[i]]
events.append((2*y[-1], +1))
events.append((2*y[-1]+1, -1))
events.sort()
result = cnt = 0
for _, c in events:
cnt += c
result = max(result, cnt)
return result