Medium
Maximum Median Sum of Subsequences of Size 3 — Python
Full explanation · Time O(nlogn) · Space O(1)
# Time: O(nlogn)
# Space: O(1)
# sort, greedy
class Solution(object):
def maximumMedianSum(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
nums.sort()
return sum(nums[i] for i in xrange(len(nums)//3, len(nums), 2))