Hard
Maximum Hamming Distances — C++
Full explanation · Time O(m * 2^m) · Space O(2^m)
// Time: O(m * 2^m)
// Space: O(2^m)
// bitmasks, knapsack dp
class Solution {
public:
vector<int> maxHammingDistances(vector<int>& nums, int m) {
vector<int> dp(1 << m, -1);
for (const auto& x: nums) {
dp[x] = 0;
}
for (int i = 0; i < m; ++i) {
vector<int> new_dp(dp);
for (int mask = 0; mask < (1 << m); ++mask) {
if (dp[mask ^ (1 << i)] != -1) {
new_dp[mask] = max(new_dp[mask], dp[mask ^ (1 << i)] + 1);
}
}
dp = move(new_dp);
}
vector<int> result(size(nums));
for (int i = 0; i < size(nums); ++i) {
result[i] = dp[nums[i]];
}
return result;
}
};
// Time: O(m * 2^m)
// Space: O(2^m)
// bitmasks, bfs
class Solution2 {
public:
vector<int> maxHammingDistances(vector<int>& nums, int m) {
vector<int> q;
vector<int> dist(1 << m, -1);
for (const auto& x : nums) {
if (dist[x] != -1) {
continue;
}
dist[x] = 0;
q.emplace_back(x);
}
for (int d = 0; !empty(q);) {
++d;
vector<int> new_q;
for (const auto& u : q) {
for (int i = 0; i < m; ++i) {
if (dist[u ^ (1 << i)] != -1) {
continue;
}
dist[u ^ (1 << i)] = d;
new_q.emplace_back(u ^ (1 << i));
}
}
q = move(new_q);
}
vector<int> result(size(nums));
for (int i = 0; i < size(nums); ++i) {
result[i] = m - dist[((1 << m) - 1) ^ nums[i]];
}
return result;
}
};