Medium
Maximum Good Subarray Sum — Python
Full explanation · Time O(n) · Space O(n)
# Time: O(n)
# Space: O(n)
import collections
# prefix sum
class Solution(object):
def maximumSubarraySum(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: int
"""
prefix = collections.defaultdict(lambda: float("inf"))
curr = 0
result = float("-inf")
for x in nums:
prefix[x] = min(prefix[x], curr)
curr += x
result = max(result, curr-prefix[x-k], curr-prefix[x+k])
return result if result != float("-inf") else 0