Hard
Maximum Good People Based on Statements — C++
Full explanation · Time O(n^2 * 2^n) · Space O(1)
// Time: O(n^2 * 2^n)
// Space: O(1)
// brute force, bitmask
class Solution {
public:
int maximumGood(vector<vector<int>>& statements) {
auto check = [&statements](int mask) {
for (int i = 0; i < size(statements); ++i) {
if (((mask >> i) & 1) == 0) {
continue;
}
for (int j = 0; j < size(statements[i]); ++j) {
if (statements[i][j] != 2 && ((mask >> j) & 1) != statements[i][j]) {
return false;
}
}
}
return true;
};
const int total = 1 << size(statements);
int result = 0;
for (int mask = 0; mask < total; ++mask) {
if (check(mask)) {
result = max(result, __builtin_popcount(mask));
}
}
return result;
}
};