Maximum Frequency of an Element After Performing Operations II — Python

# Time:  O(nlogn)
# Space: O(n)

import collections


# sort, freq table, two pointers, sliding window
class Solution(object):
    def maxFrequency(self, nums, k, numOperations):
        """
        :type nums: List[int]
        :type k: int
        :type numOperations: int
        :rtype: int
        """
        nums.sort()
        result = 0
        left, right = 0, -1
        cnt = collections.defaultdict(int)
        for i in xrange(len(nums)):
            while right+1 < len(nums) and nums[right+1]-nums[i] <= k:
                cnt[nums[right+1]] += 1 
                right += 1
            while nums[i]-nums[left] > k:
                cnt[nums[left]] -= 1
                left += 1
            result = max(result, cnt[nums[i]]+min((right-left+1)-cnt[nums[i]], numOperations))
        left = 0
        for right in xrange(len(nums)):
            while nums[left]+k < nums[right]-k:
                left += 1
            result = max(result, min(right-left+1, numOperations))
        return result
    

# Time:  O(nlogn)
# Space: O(n)
import collections


# sort, freq table, difference array, line sweep
class Solution2(object):
    def maxFrequency(self, nums, k, numOperations):
        """
        :type nums: List[int]
        :type k: int
        :type numOperations: int
        :rtype: int
        """
        cnt = collections.defaultdict(int)  # defaultdict is much faster than Counter
        for x in nums:
            cnt[x] += 1
        diff = defaultdict(int)
        for x in nums:
            diff[x] += 0
            diff[x-k] += 1
            diff[x+k+1] -= 1
        result = curr = 0
        for x, c in sorted(diff.iteritems()):
            curr += c
            result = max(result, cnt[x]+min(curr-cnt[x], numOperations))
        return result