Hard
Maximum Element-Sum of a Complete Subset of Indices — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n * (1 + 1/4 + 1/9 + ...)) = O(pi^2 / 6 * n) = O(n), see https://en.wikipedia.org/wiki/Basel_problem
// Space: O(1)
// number theory, basel problem
class Solution {
public:
long long maximumSum(vector<int>& nums) {
int64_t result = 0;
for (int i = 1; i <= size(nums); ++i) {
int64_t curr = 0;
for (int x = 1; i * x * x - 1 < size(nums); ++x) {
curr += nums[i * x * x - 1];
}
result = max(result, curr);
}
return result;
}
};