Easy
Maximum Distance in Arrays — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
int maxDistance(vector<vector<int>>& arrays) {
int result = 0;
int min_val = arrays[0].front(), max_val = arrays[0].back();
for (int i = 1; i < arrays.size(); ++i) {
result = max(result,
max(max_val - arrays[i].front(),
arrays[i].back() - min_val));
min_val = min(min_val, arrays[i].front());
max_val = max(max_val, arrays[i].back());
}
return result;
}
};