Medium
Maximum Candies Allocated to K Children — C++
Full explanation · Time O(nlogr) · Space O(1)
// Time: O(nlogr), r is max(candies)
// Space: O(1)
// binary search
class Solution {
public:
int maximumCandies(vector<int>& candies, long long k) {
const auto& check = [&candies, &k](const auto& x) {
return accumulate(cbegin(candies), cend(candies), 0ll,
[&x](const auto& total, const auto& v) {
return total + v / x;
}) >= k;
};
int left = 1, right = *max_element(cbegin(candies), cend(candies));
while (left <= right) {
const auto& mid = left + (right - left) / 2;
if (!check(mid)) {
right = mid - 1;
} else {
left = mid + 1;
}
}
return right;
}
};