Hard
Maximum Bitwise AND After Increment Operations — Python
Full explanation · Time O(nlogr) · Space O(n)
# Time: O(nlogr)
# Space: O(n)
import random
# bitmasks, greedy, quick select
class Solution(object):
def maximumAND(self, nums, k, m):
"""
:type nums: List[int]
:type k: int
:type m: int
:rtype: int
"""
def nth_element(nums, n, left=0, compare=lambda a, b: a < b):
def tri_partition(nums, left, right, target, compare):
mid = left
while mid <= right:
if nums[mid] == target:
mid += 1
elif compare(nums[mid], target):
nums[left], nums[mid] = nums[mid], nums[left]
left += 1
mid += 1
else:
nums[mid], nums[right] = nums[right], nums[mid]
right -= 1
return left, right
right = len(nums)-1
while left <= right:
pivot_idx = random.randint(left, right)
pivot_left, pivot_right = tri_partition(nums, left, right, nums[pivot_idx], compare)
if pivot_left <= n <= pivot_right:
return
elif pivot_left > n:
right = pivot_left-1
else: # pivot_right < n.
left = pivot_right+1
result = 0
for i in reversed(xrange((max(nums)+k).bit_length())):
target = result|(1<<i)
costs = []
for x in nums:
l = (target&~x).bit_length()
mask = (1<<l)-1
costs.append((target&mask)-(x&mask))
nth_element(costs, m-1)
if sum(costs[i] for i in xrange(m)) <= k:
result |= 1<<i
return result
# Time: O(nlogn * logr)
# Space: O(n)
# bitmasks, greedy, sort
class Solution2(object):
def maximumAND(self, nums, k, m):
"""
:type nums: List[int]
:type k: int
:type m: int
:rtype: int
"""
result = 0
for i in reversed(xrange((max(nums)+k).bit_length())):
target = result|(1<<i)
costs = []
for x in nums:
l = (target&~x).bit_length()
mask = (1<<l)-1
costs.append((target&mask)-(x&mask))
costs.sort()
if sum(costs[i] for i in xrange(m)) <= k:
result |= 1<<i
return result