Medium
Maximum Bags With Full Capacity of Rocks — Python
Full explanation · Time O(nlogn) · Space O(1)
# Time: O(nlogn)
# Space: O(1)
# sort, greedy
class Solution(object):
def maximumBags(self, capacity, rocks, additionalRocks):
"""
:type capacity: List[int]
:type rocks: List[int]
:type additionalRocks: int
:rtype: int
"""
for i in xrange(len(capacity)):
capacity[i] -= rocks[i]
capacity.sort()
for i, c in enumerate(capacity):
if c > additionalRocks:
return i
additionalRocks -= c
return len(capacity)