Easy
Maximum Average Subtree — Python
Full explanation · Time O(n) · Space O(h)
# Time: O(n)
# Space: O(h)
# Definition for a binary tree node.
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution(object):
def maximumAverageSubtree(self, root):
"""
:type root: TreeNode
:rtype: float
"""
def maximumAverageSubtreeHelper(root, result):
if not root:
return [0.0, 0]
s1, n1 = maximumAverageSubtreeHelper(root.left, result)
s2, n2 = maximumAverageSubtreeHelper(root.right, result)
s = s1+s2+root.val
n = n1+n2+1
result[0] = max(result[0], s / n)
return [s, n]
result = [0]
maximumAverageSubtreeHelper(root, result)
return result[0]