Hard
Maximize Consecutive Elements in an Array After Modification — C++
Full explanation · Time O(nlogn) · Space O(1)
// Time: O(nlogn)
// Space: O(1)
// sort, dp
class Solution {
public:
int maxSelectedElements(vector<int>& nums) {
sort(begin(nums), end(nums));
int result = 1;
vector<int> dp(2, 1); // dp[i]: the maximum length of a consecutive sequence ending with x+i, where x is the last visited value
for (int i = 1; i < size(nums); ++i) {
if (nums[i] == nums[i - 1]) {
dp[1] = dp[0] + 1;
} else if (nums[i] == nums[i - 1] + 1) {
++dp[0];
++dp[1];
} else if (nums[i] == nums[i - 1] + 2) {
dp[0] = dp[1] + 1;
dp[1] = 1;
} else {
dp[0] = dp[1] = 1;
}
result = max({result, dp[0], dp[1]});
}
return result;
}
};
// Time: O(nlogn)
// Space: O(n)
// sort, dp
class Solution2 {
public:
int maxSelectedElements(vector<int>& nums) {
sort(begin(nums), end(nums));
unordered_map<int, int> dp;
dp[nums[0]] = dp[nums[0] + 1] = 1;
for (int i = 1; i < size(nums); ++i) {
if (nums[i] == nums[i - 1]) {
dp[nums[i] + 1] = dp[nums[i]] + 1;
} else if (nums[i] == nums[i - 1] + 1) {
dp[nums[i] + 1] = dp[nums[i]] + 1;
dp[nums[i]] = dp[nums[i] - 1] + 1;
} else if (nums[i] == nums[i - 1] + 2) {
dp[nums[i]] = dp[nums[i] - 1] + 1;
dp[nums[i] + 1] = 1;
} else {
dp[nums[i]] = dp[nums[i] + 1] = 1;
}
}
return max_element(cbegin(dp), cend(dp), [](const auto& a, const auto& b) { return a.second < b.second; })->second;
}
};
// Time: O(nlogn)
// Space: O(n)
// sort, dp
class Solution3 {
public:
int maxSelectedElements(vector<int>& nums) {
sort(begin(nums), end(nums));
unordered_map<int, int> dp;
for (const auto& x : nums) {
dp[x + 1] = dp[x] + 1;
dp[x] = dp[x - 1] + 1;
}
return max_element(cbegin(dp), cend(dp), [](const auto& a, const auto& b) { return a.second < b.second; })->second;
}
};