Hard
Max Chunks To Make Sorted II — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
// mono stack solution
class Solution {
public:
int maxChunksToSorted(vector<int>& arr) {
vector<int> increasing_stk;
for (const auto& num : arr) {
int max_num = empty(increasing_stk) ? num : max(increasing_stk.back(), num);
while (!empty(increasing_stk) && increasing_stk.back() > num) {
increasing_stk.pop_back();
}
increasing_stk.emplace_back(max_num);
}
return size(increasing_stk);
}
};
// Time: O(nlogn)
// Space: O(n)
class Solution2 {
public:
int maxChunksToSorted(vector<int>& arr) {
vector<int> idxs(arr.size());
iota(idxs.begin(), idxs.end(), 0);
sort(idxs.begin(), idxs.end(),
[&](int i1, int i2) {
return arr[i1] != arr[i2] ? arr[i1] < arr[i2] : i1 < i2;
});
int result = 0;
for (auto i = 0, max_i = 0; i < idxs.size(); ++i) {
max_i = max(max_i, idxs[i]);
if (max_i == i) ++result;
}
return result;
}
};