Medium
Lowest Common Ancestor of a Binary Tree IV — Python
Full explanation · Time O(n) · Space O(h)
# Time: O(n)
# Space: O(h)
# Definition for a binary tree node.
class TreeNode(object):
def __init__(self, x):
pass
class Solution(object):
def lowestCommonAncestor(self, root, nodes):
"""
:type root: TreeNode
:type nodes: List[TreeNode]
"""
def iter_dfs(root, lookup):
result = [0]
stk = [(1, (root, result))]
while stk:
step, args = stk.pop()
if step == 1:
node, ret = args
if not node or node in lookup:
ret[0] = node
continue
ret1, ret2 = [None], [None]
stk.append((2, (node, ret1, ret2, ret)))
stk.append((1, (node.right, ret2)))
stk.append((1, (node.left, ret1)))
elif step == 2:
node, ret1, ret2, ret = args
if ret1[0] and ret2[0]:
ret[0] = node
else:
ret[0] = ret1[0] or ret2[0]
return result[0]
return iter_dfs(root, set(nodes))
# Time: O(n)
# Space: O(h)
class Solution2(object):
def lowestCommonAncestor(self, root, nodes):
"""
:type root: TreeNode
:type nodes: List[TreeNode]
"""
def dfs(node, lookup):
if not node or node in lookup:
return node
left, right = dfs(node.left, lookup), dfs(node.right, lookup)
if left and right:
return node
return left or right
return dfs(root, set(nodes))