Hard
Longest Valid Parentheses — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
int longestValidParentheses(string s) {
return max(length(s.begin(), s.end(), '('), length(s.rbegin(), s.rend(), ')'));
}
private:
template<typename T>
int length(T begin, T end, char c) {
int len = 0, depth = 0;
T start = begin;
for (T it = begin; it != end; ++it) {
if (*it == c) {
++depth;
} else {
--depth;
if (depth < 0) {
start = next(it);
depth = 0;
} else {
if (depth == 0) {
len = max(len, static_cast<int>(distance(start, it)) + 1);
}
}
}
}
return len;
}
};