Easy

Longest Uncommon Subsequence I — Python

Full explanation · Time O(min(a, b)) · Space O(1)

# Time:  O(min(a, b))
# Space: O(1)

class Solution(object):
    def findLUSlength(self, a, b):
        """
        :type a: str
        :type b: str
        :rtype: int
        """
        if a == b:
            return -1
        return max(len(a), len(b))