Easy
Longest Strictly Increasing or Strictly Decreasing Subarray — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
# array
class Solution(object):
def longestMonotonicSubarray(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
result = cnt = 1 if len(nums) == 1 or cmp(nums[0], nums[1]) == 0 else 2
for i in xrange(2, len(nums)):
cnt = 1 if cmp(nums[i-1], nums[i]) == 0 else cnt+1 if cmp(nums[i-2], nums[i-1]) == cmp(nums[i-1], nums[i]) else 2
result = max(result, cnt)
return result
# Time: O(n)
# Space: O(1)
# array
class Solution2(object):
def longestMonotonicSubarray(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
result = cnt1 = cnt2 = 1
for i in xrange(1, len(nums)):
cnt1 = cnt1+1 if nums[i-1] < nums[i] else 1
cnt2 = cnt2+1 if nums[i-1] > nums[i] else 1
result = max(result, cnt1, cnt2)
return result
# Time: O(n)
# Space: O(1)
# array
class Solution3(object):
def longestMonotonicSubarray(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
def f(compare):
result = l = 0
for i in xrange(len(nums)):
l += 1
if i+1 == len(nums) or not compare(nums[i], nums[i+1]):
result = max(result, l)
l = 0
return result
return max(f(lambda x, y: x < y), f(lambda x, y: x > y))