Easy

Longest Continuous Increasing SubsequenceC++

Full explanation · Time O(n) · Space O(1)

// Time:  O(n)
// Space: O(1)

class Solution {
public:
    int findLengthOfLCIS(vector<int>& nums) {
        int result = 0, count = 0;
        for (int i = 0; i < nums.size(); ++i) {
            if (i == 0 || nums[i - 1] < nums[i]) {
                result = max(result, ++count);
            } else {
                count = 1;
            }
        }
        return result;
    }   
};