Easy
Longest Continuous Increasing Subsequence — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
int findLengthOfLCIS(vector<int>& nums) {
int result = 0, count = 0;
for (int i = 0; i < nums.size(); ++i) {
if (i == 0 || nums[i - 1] < nums[i]) {
result = max(result, ++count);
} else {
count = 1;
}
}
return result;
}
};