Easy
Longest Alternating Subarray — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
// array
class Solution {
public:
int alternatingSubarray(vector<int>& nums) {
int result = -1, l = -1;
for (int i = 0; i + 1 < size(nums); ++i) {
if (l != -1 && nums[i - 1] == nums[i + 1]) {
++l;
} else {
l = nums[i + 1] - nums[i] == 1 ? 2 : -1;
}
result = max(result, l);
}
return result;
}
};