Easy
Linked List Cycle — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
class ListNode(object):
def __init__(self, x):
self.val = x
self.next = None
class Solution(object):
# @param head, a ListNode
# @return a boolean
def hasCycle(self, head):
fast, slow = head, head
while fast and fast.next:
fast, slow = fast.next.next, slow.next
if fast is slow:
return True
return False