Easy

Lexicographically Smallest Palindrome — C++

Full explanation · Time O(n) · Space O(1)

// Time:  O(n)
// Space: O(1)

// greedy
class Solution {
public:
    string makeSmallestPalindrome(string s) {
        for (int i = 0; i < size(s) / 2; ++i) {
            s[i] = s[(size(s) - 1) - i] = min(s[i], s[(size(s) - 1) - i]);
        }
        return s;
    }
};