Hard
Lexicographically Maximum MEX Array — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
// hash table, prefix sum, greedy
class Solution {
public:
vector<int> maximumMEX(vector<int>& nums) {
int ver = -1;
vector<int> lookup(size(nums), ver);
vector<int> suffix(size(nums));
++ver;
int mex = 0;
for (int i = size(nums) - 1; i >= 0; --i) {
if (nums[i] < size(lookup)) {
lookup[nums[i]] = ver;
}
while (mex < size(lookup) && lookup[mex] == ver) {
++mex;
}
suffix[i] = mex;
}
vector<int> result;
++ver;
mex = 0;
int j = 0;
for (int i = 0; i < size(nums); ++i) {
if (!suffix[j]) {
break;
}
if (nums[i] < size(lookup)) {
lookup[nums[i]] = ver;
}
while (mex < size(lookup) && lookup[mex] == ver) {
++mex;
}
if (mex != suffix[j]) {
continue;
}
result.emplace_back(mex);
++ver;
mex = 0;
j = i + 1;
}
result.resize(size(result) + (size(nums) - j));
return result;
}
};
// Time: O(n)
// Space: O(n)
// hash table, freq table, greedy
class Solution2 {
public:
vector<int> maximumMEX(vector<int>& nums) {
int ver = -1;
vector<int> lookup(size(nums), ver);
vector<int> cnt(size(nums));
++ver;
int mex = 0;
for (int i = 0; i < size(nums); ++i) {
if (nums[i] < size(lookup)) {
lookup[nums[i]] = ver;
++cnt[nums[i]];
}
while (mex < size(lookup) && lookup[mex] == ver) {
++mex;
}
}
int suffix = mex, new_suffix = mex;
vector<int> result;
++ver;
mex = 0;
int j = 0;
for (int i = 0; i < size(nums); ++i) {
if (!suffix) {
break;
}
if (nums[i] < size(lookup)) {
lookup[nums[i]] = ver;
if (!--cnt[nums[i]] && nums[i] < new_suffix) {
new_suffix = nums[i];
}
}
while (mex < size(lookup) && lookup[mex] == ver) {
++mex;
}
if (mex != suffix) {
continue;
}
result.emplace_back(mex);
++ver;
mex = 0;
j = i + 1;
suffix = new_suffix;
}
result.resize(size(result) + (size(nums) - j));
return result;
}
};