Easy
Letter Case Permutation — Python
Full explanation · Time O(n * 2^n) · Space O(1)
# Time: O(n * 2^n)
# Space: O(n * 2^n)
class Solution(object):
def letterCasePermutation(self, S):
"""
:type S: str
:rtype: List[str]
"""
result = [[]]
for c in S:
if c.isalpha():
for i in xrange(len(result)):
result.append(result[i][:])
result[i].append(c.lower())
result[-1].append(c.upper())
else:
for s in result:
s.append(c)
return map("".join, result)