Easy
Largest Perimeter Triangle — Python
Full explanation · Time O(nlogn) · Space O(1)
# Time: O(nlogn)
# Space: O(1)
class Solution(object):
def largestPerimeter(self, A):
"""
:type A: List[int]
:rtype: int
"""
A.sort()
for i in reversed(xrange(len(A) - 2)):
if A[i] + A[i+1] > A[i+2]:
return A[i] + A[i+1] + A[i+2]
return 0