Medium
Largest Element in an Array after Merge Operations — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
# greedy
class Solution(object):
def maxArrayValue(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
result = curr = 0
for i in reversed(xrange(len(nums))):
if nums[i] > curr:
curr = 0
curr += nums[i]
result = max(result, curr)
return result