Hard
Kth Smallest Number in Multiplication Table — C++
Full explanation · Time O(m * log(m * n)) · Space O(1)
// Time: O(m * log(m * n))
// Space: O(1)
class Solution {
public:
int findKthNumber(int m, int n, int k) {
int left = 1, right = m * n;
while (left <= right) {
const auto mid = left + (right - left) / 2;
if (count(mid, m, n) >= k) {
right = mid - 1;
} else {
left = mid + 1;
}
}
return left;
}
private:
int count(int target, int m, int n) {
auto count = 0;
for (int i = 1; i <= m; ++i) {
count += min(target / i , n);
}
return count;
}
};