Medium

Knight DialerPython

Full explanation · Time O(logn) · Space O(1)

# Time:  O(logn)
# Space: O(1)

import itertools


class Solution(object):
    def knightDialer(self, N):
        """
        :type N: int
        :rtype: int
        """
        def matrix_expo(A, K):
            result = [[int(i==j) for j in xrange(len(A))] \
                      for i in xrange(len(A))]
            while K:
                if K % 2:
                    result = matrix_mult(result, A)
                A = matrix_mult(A, A)
                K /= 2
            return result

        def matrix_mult(A, B):
            ZB = zip(*B)
            return [[sum(a*b for a, b in itertools.izip(row, col)) % M \
                     for col in ZB] for row in A]
        
        M = 10**9 + 7
        T = [[0, 0, 0, 0, 1, 0, 1, 0, 0, 0],
             [0, 0, 0, 0, 0, 0, 1, 0, 1, 0],
             [0, 0, 0, 0, 0, 0, 0, 1, 0, 1],
             [0, 0, 0, 0, 1, 0, 0, 0, 1, 0],
             [1, 0, 0, 1, 0, 0, 0, 0, 0, 1],
             [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
             [1, 1, 0, 0, 0, 0, 0, 1, 0, 0],
             [0, 0, 1, 0, 0, 0, 1, 0, 0, 0],
             [0, 1, 0, 1, 0, 0, 0, 0, 0, 0],
             [0, 0, 1, 0, 1, 0, 0, 0, 0, 0]]
        return sum(map(sum, matrix_expo(T, N-1))) % M


# Time:  O(n)
# Space: O(1)
class Solution2(object):
    def knightDialer(self, N):
        """
        :type N: int
        :rtype: int
        """
        M = 10**9 + 7
        moves = [[4, 6], [6, 8], [7, 9], [4, 8], [3, 9, 0], [],
                 [1, 7, 0], [2, 6], [1, 3], [2, 4]]

        dp = [[1 for _ in xrange(10)] for _ in xrange(2)]
        for i in xrange(N-1):
            dp[(i+1) % 2] = [0] * 10
            for j in xrange(10):
                for nei in moves[j]:
                    dp[(i+1) % 2][nei] += dp[i % 2][j]
                    dp[(i+1) % 2][nei] %= M
        return sum(dp[(N-1) % 2]) % M