Easy
Jewels and Stones — C++
Full explanation · Time O(m + n) · Space O(n)
// Time: O(m + n)
// Space: O(n)
class Solution {
public:
int numJewelsInStones(string J, string S) {
unordered_set<char> lookup;
for (const auto& j : J) {
lookup.emplace(j);
}
int result = 0;
for (const auto& s : S) {
result += lookup.count(s);
}
return result;
}
};