Easy
Intersection of Multiple Arrays — C++
Full explanation · Time O(n * l + r) · Space O(l)
// Time: O(n * l + r), n = len(nums), l = len(nums[0])
// Space: O(r), r = max(nums)-min(nums)
// freq table, counting sort
class Solution {
public:
vector<int> intersection(vector<vector<int>>& nums) {
static const int MAX_NUM = 1000;
vector<int> cnt(MAX_NUM + 1);
for (const auto& num : nums) {
for (const auto& x : num) {
++cnt[x];
}
}
vector<int> result;
for (int i = 1; i <= MAX_NUM; ++i) {
if (cnt[i] == size(nums)) {
result.emplace_back(i);
}
}
return result;
}
};
// Time: O(n * l + r), n = len(nums), l = len(nums[0]), r = max(nums)-min(nums)
// Space: O(l)
// hash table, counting sort
class Solution2 {
public:
vector<int> intersection(vector<vector<int>>& nums) {
unordered_set<int> lookup(cbegin(nums[0]), cend(nums[0]));
for (int i = 1; i < size(nums); ++i) {
unordered_set<int> new_lookup;
for (const auto& x : nums[i]) {
if (lookup.count(x)) {
new_lookup.emplace(x);
}
}
lookup = move(new_lookup);
}
if (empty(lookup)) {
return {};
}
const int mn = *min_element(cbegin(lookup), cend(lookup));
const int mx = *max_element(cbegin(lookup), cend(lookup));
vector<int> result;
for (int i = mn; i <= mx; ++i) {
if (lookup.count(i)) {
result.emplace_back(i);
}
}
return result;
}
};
// Time: O(n * l + llogl), n = len(nums), l = len(nums[0])
// Space: O(l)
// hash table, sort
class Solution3 {
public:
vector<int> intersection(vector<vector<int>>& nums) {
unordered_set<int> lookup(cbegin(nums[0]), cend(nums[0]));
for (int i = 1; i < size(nums); ++i) {
unordered_set<int> new_lookup;
for (const auto& x : nums[i]) {
if (lookup.count(x)) {
new_lookup.emplace(x);
}
}
lookup = move(new_lookup);
}
vector<int> result(cbegin(lookup), cend(lookup));
sort(begin(result), end(result));
return result;
}
};