Medium
Insertion Sort List — Python
Full explanation · Time O(n^2) · Space O(1)
# Time: O(n ^ 2)
# Space: O(1)
class ListNode(object):
def __init__(self, x):
self.val = x
self.next = None
def __repr__(self):
if self:
return "{} -> {}".format(self.val, repr(self.next))
else:
return "Nil"
class Solution(object):
# @param head, a ListNode
# @return a ListNode
def insertionSortList(self, head):
if head is None or self.isSorted(head):
return head
dummy = ListNode(-2147483648)
dummy.next = head
cur, sorted_tail = head.next, head
while cur:
prev = dummy
while prev.next.val < cur.val:
prev = prev.next
if prev == sorted_tail:
cur, sorted_tail = cur.next, cur
else:
cur.next, prev.next, sorted_tail.next = prev.next, cur, cur.next
cur = sorted_tail.next
return dummy.next
def isSorted(self, head):
while head and head.next:
if head.val > head.next.val:
return False
head = head.next
return True