Medium
Gray Code — C++
Full explanation · Time O(2^n) · Space O(1)
// Time: (2^n)
// Space: O(1)
class Solution {
public:
vector<int> grayCode(int n) {
vector<int> result = {0};
for (int i = 0; i < n; ++i) {
for (int j = result.size() - 1; j >= 0; --j) {
result.emplace_back(1 << i | result[j]);
}
}
return result;
}
};
// Time: (2^n)
// Space: O(1)
// Proof of closed form formula could be found here:
// http://math.stackexchange.com/questions/425894/proof-of-closed-form-formula-to-convert-a-binary-number-to-its-gray-code
class Solution2 {
public:
vector<int> grayCode(int n) {
vector<int> result;
for (int i = 0; i < 1 << n; ++i) {
result.emplace_back(i >> 1 ^ i);
}
return result;
}
};