Medium
Good Indices in a Digit String — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
// math, sliding window
class Solution {
public:
vector<int> goodIndices(string s) {
vector<int> result;
for (int i = 0, curr = 0, base = 1; i < size(s); ++i) {
if (i == base * 10) {
base *= 10;
}
curr = (curr % base) * 10 + (s[i] - '0');
if (curr == i) {
result.emplace_back(i);
}
}
return result;
}
};