Medium
Frog Jump II — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
// greedy
class Solution {
public:
int maxJump(vector<int>& stones) {
if (size(stones) == 2) {
return stones[1] - stones[0];
}
int result = 0;
for (int i = 0; i + 2 < size(stones); ++i) {
result = max(result, stones[i + 2] - stones[i]);
}
return result;
}
};