Hard
Find the Sum of the Power of All Subsequences — Python
Full explanation · Time O(n * k) · Space O(k)
# Time: O(n * k)
# Space: O(k)
# dp, combinatorics
class Solution(object):
def sumOfPower(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: int
"""
MOD = 10**9+7
dp = [0]*(k+1)
dp[0] = 1
for x in nums:
for i in reversed(xrange(k+1)):
dp[i] = (dp[i]+(dp[i]+(dp[i-x] if i-x >= 0 else 0)))%MOD
return dp[k]