Medium
Find the Count of Numbers Which Are Not Special — Python
Full explanation · Time precompute: O(sqrt(r)) runtime: O(logr) · Space O(sqrt(r))
# Time: precompute: O(sqrt(r))
# runtime: O(logr + log(sqrt(r))) = O(logr)
# Space: O(sqrt(r))
import bisect
# number theory, binary search
def linear_sieve_of_eratosthenes(n): # Time: O(n), Space: O(n)
primes = []
spf = [-1]*(n+1) # the smallest prime factor
for i in xrange(2, n+1):
if spf[i] == -1:
spf[i] = i
primes.append(i)
for p in primes:
if i*p > n or p > spf[i]:
break
spf[i*p] = p
return primes # len(primes) = O(n/(logn-1)), reference: https://math.stackexchange.com/questions/264544/how-to-find-number-of-prime-numbers-up-to-to-n
MAX_R = 10**9
PRIMES = linear_sieve_of_eratosthenes(int(MAX_R**0.5))
class Solution(object):
def nonSpecialCount(self, l, r):
"""
:type l: int
:type r: int
:rtype: int
"""
def count(x):
return x-bisect.bisect_right(PRIMES, int(x**0.5))
return count(r)-count(l-1)