Hard
Find the Closest Palindrome — Python
Full explanation · Time O(l) · Space O(l)
# Time: O(l)
# Space: O(l)
class Solution(object):
def nearestPalindromic(self, n):
"""
:type n: str
:rtype: str
"""
l = len(n)
candidates = set((str(10**l + 1), str(10**(l - 1) - 1)))
prefix = int(n[:(l + 1)/2])
for i in map(str, (prefix-1, prefix, prefix+1)):
candidates.add(i + [i, i[:-1]][l%2][::-1])
candidates.discard(n)
return min(candidates, key=lambda x: (abs(int(x) - int(n)), int(x)))