Easy
Find N Unique Integers Sum up to Zero — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
vector<int> sumZero(int n) {
vector<int> result;
for (int i = -(n / 2); i <= (n / 2); ++i) {
if (i == 0 && n % 2 == 0) {
continue;
}
result.emplace_back(i);
}
return result;
}
};