Easy
Find Missing and Repeated Values — C++
Full explanation · Time O(n^2) · Space O(1)
// Time: O(n^2)
// Space: O(1)
// bit manipulation
class Solution {
public:
vector<int> findMissingAndRepeatedValues(vector<vector<int>>& grid) {
const int n = size(grid);
int a_xor_b = 0;
for (int i = 0; i < n * n; ++i) {
const int r = i / n, c = i % n;
a_xor_b ^= grid[r][c] ^ (i + 1);
}
const int base = a_xor_b & -a_xor_b;
vector<int> result(2);
for (int i = 0; i < n * n; ++i) {
const int r = i / n, c = i % n;
result[((i + 1) & base) != 0 ? 1 : 0] ^= i + 1;
result[(grid[r][c] & base) != 0 ? 1 : 0] ^= grid[r][c];
}
for (int r = 0; r < n; ++r) {
for (int c = 0; c < n; ++c) {
if (grid[r][c] == result[1]) {
swap(result[0], result[1]);
return result;
}
}
}
return result;
}
};
// Time: O(n^2)
// Space: O(n^2)
// freq table
class Solution2 {
public:
vector<int> findMissingAndRepeatedValues(vector<vector<int>>& grid) {
const int n = size(grid);
vector<int> cnt(n * n);
for (int r = 0; r < n; ++r) {
for (int c = 0; c < n; ++c) {
++cnt[grid[r][c] - 1];
}
}
vector<int> result(2);
for (int i = 0; i < n * n; ++i) {
if (cnt[i] == 2) {
result[0] = i + 1;
} else if (cnt[i] == 0) {
result[1] = i + 1;
}
}
return result;
}
};