Find Minimum Time to Reach Last Room I
Time O(n * m * log(n * m)) · Space O(n * m) · Official statement on LeetCode
Solutions
// Time: O(n * m * logn(n * m))
// Space: O(n * m)
// dijkstra's algorithm
class Solution {
public:
int minTimeToReach(vector<vector<int>>& moveTime) {
static const int INF = numeric_limits<int>::max();
static const vector<pair<int, int>> DIRECTIONS = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};
const auto& dijkstra = [&](const pair<int, int>& start, const pair<int, int>& target) {
vector<vector<int>> dist(size(moveTime), vector<int>(size(moveTime[0]), INF));
dist[start.first][start.second] = 0;
priority_queue<tuple<int, int, int>, vector<tuple<int, int, int>>, greater<tuple<int, int, int>>> min_heap;
min_heap.emplace(dist[start.first][start.second], start.first, start.second);
while (!empty(min_heap)) {
const auto [curr, i, j] = min_heap.top(); min_heap.pop();
if (curr != dist[i][j]) {
continue;
}
if (pair(i, j) == target) {
break;
}
for (const auto& [di, dj] : DIRECTIONS) {
const int ni = i + di, nj = j + dj;
const int c = 1;
if (!(0 <= ni && ni < size(moveTime) && 0 <= nj && nj < size(moveTime[0]) && dist[ni][nj] > max(moveTime[ni][nj], curr) + c)) {
continue;
}
dist[ni][nj] = max(moveTime[ni][nj], curr) + c;
min_heap.emplace(dist[ni][nj], ni, nj);
}
}
return dist[target.first][target.second];
};
return dijkstra({0, 0}, {size(moveTime) - 1, size(moveTime[0]) - 1});
}
};
Beginner Explanation
What is Find Minimum Time to Reach Last Room I?
Find Minimum Time to Reach Last Room I (LeetCode #3341) is a Medium problem that primarily trains graph.
How to think about it
- Restate the goal in your own words before coding.
- Work a tiny example by hand so the invariant becomes obvious.
- Identify the pattern — this problem aligns with graph and dijkstras algorithm.
- Only then translate the idea into code.
Why this problem matters
It sits in the sweet spot of interview difficulty: multiple valid approaches, clear trade-offs. Official solution notes mention: Graph, Dijkstra's Algorithm.
AlgoForge explanations are original teaching notes. Always open the official problem statement on LeetCode for constraints and examples.
Interview Walkthrough
Interview approach for Find Minimum Time to Reach Last Room I
Opening (30–60 seconds)
- Clarify inputs/outputs and edge cases (empty input, single element, duplicates, overflow).
- State a brute force so the interviewer knows you can solve it naively.
- Propose the optimal direction tied to graph and dijkstras algorithm.
Core solution narrative
- Define the state you track (pointers, DP cell, set membership, stack top, etc.).
- Explain the transition when you process the next element.
- Call out time (O(n * m * log(n * m))) and space (O(n * m)) before coding.
- Code cleanly; narrate variable names.
What interviewers listen for
- Correctness on edge cases
- Complexity honesty
- Ability to discuss trade-offs (e.g., hash map space vs. sort + two pointers)
Follow-up questions they may ask
- Can you solve it with less memory?
- What if the input stream is infinite / doesn't fit in RAM?
- How would tests look for adversarial inputs?
Optimized Approach
Optimized solution notes
The reference solutions on AlgoForge target O(n * m * log(n * m)) time and O(n * m) space.
Pattern focus: graph and dijkstras algorithm
Use the pattern as a checklist:
- graph — confirm the invariant holds after each step
- dijkstras algorithm — confirm the invariant holds after each step
Multiple methods appear in the source solutions — compare them and explain when each is preferable.
Implementation tips
- Prefer readable names over micro-optimizations in interviews.
- Extract helpers only when they clarify (e.g., expand-around-center, DFS visit).
- After AC-level logic, re-scan for off-by-one and null checks.
Complexity Analysis
Complexity
| Measure | Bound |
|---|---|
| Time | O(n * m * log(n * m)) |
| Space | O(n * m) |
How to justify this in an interview
- Time: count loops, map/set operations, and recursive branching; state average vs worst case if relevant.
- Space: include hash maps, recursion stack, and output allocation when the problem asks for it.
If your implementation differs from the reference, re-derive big-O from your code — never memorize a complexity you cannot defend.
Common Mistakes
Common mistakes on Find Minimum Time to Reach Last Room I
- Skipping edge cases — empty collections, single-element inputs, max constraints.
- Wrong invariant for graph and dijkstras algorithm — updating state too early or too late.
- Mutating input unexpectedly when the problem forbids it.
- Off-by-one in windows, ranges, or binary search bounds.
- Ignoring overflow / precision for integer arithmetic problems.
- Overengineering — jumping to an advanced structure when a simpler approach works.
Alternative Approaches
Alternatives
The source file includes more than one method. Compare:
- Primary optimized path — best complexity for typical interviews.
- Secondary approach — often brute force, sorting-based, or space-optimized variant.
Practice articulating when you would pick each (constraints, readability, follow-ups).
Edge Cases
Edge cases checklist
- Minimum input size
- Maximum input size / time limits
- Duplicates and already-sorted input
- Negative numbers / zeros (if applicable)
- Disconnected structures (graphs/trees)
- Single path vs branching recursion depth
Pattern Recognition
Spotting this pattern
Signal phrases that point to graph and dijkstras algorithm:
- Sorted input or ability to sort without changing the answer class
- Need for contiguous subarray / substring → consider sliding window
- Need for O(1) membership → hash set/map
- Optimal substructure + overlapping subproblems → DP
- Connectivity / components → graph DFS/BFS or Union-Find
Primary topics: graph.
Follow-up Interview Questions
Follow-ups
- How does the solution change if the input is a stream?
- Can you solve it in-place?
- What if duplicates must be handled differently?
- How would you parallelize the approach?
- Design tests that would break a buggy implementation.
Practice Recommendations
What to practice next
- Re-solve Find Minimum Time to Reach Last Room I in a second language (cpp, python).
- Drill 3–5 more problems tagged graph.
- Teach the solution out loud in under 5 minutes.
- Add this problem to your revision calendar in 3 days and 14 days.
Visualization
Study checklist
- Read the official problem statement on LeetCode
- Solve on paper / whiteboard first
- Implement the graph and dijkstras algorithm approach
- Verify edge cases from the checklist
- State time and space complexity aloud
- Compare with the AlgoForge reference solution
- Schedule a revision session
Revision notes
Find Minimum Time to Reach Last Room I (#3341) — Medium. Pattern: graph and dijkstras algorithm. Complexity: O(n * m * log(n * m)) time / O(n * m) space. Re-derive the invariant before coding.
FAQs
What is the time complexity of Find Minimum Time to Reach Last Room I?+
The reference solutions aim for O(n * m * log(n * m)) time and O(n * m) space. Always re-derive complexity from the code you write in the interview.
What pattern does Find Minimum Time to Reach Last Room I use?+
It primarily maps to graph and dijkstras algorithm, within the broader topic of graph.
Is Find Minimum Time to Reach Last Room I good for interviews?+
Yes — as a Medium problem it is a solid practice target. Pair it with related problems in the same pattern family for spaced repetition.
Where can I read the official statement?+
Open the official LeetCode page for constraints and examples: https://leetcode.com/problems/find-minimum-time-to-reach-last-room-i/