Hard
Find Minimum in Rotated Sorted Array II — Python
Full explanation · Time O(logn) ~ O(n) · Space O(1)
# Time: O(logn) ~ O(n)
# Space: O(1)
class Solution(object):
def findMin(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
left, right = 0, len(nums) - 1
while left < right:
mid = left + (right - left) / 2
if nums[mid] == nums[right]:
right -= 1
elif nums[mid] < nums[right]:
right = mid
else:
left = mid + 1
return nums[left]
class Solution2(object):
def findMin(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
left, right = 0, len(nums) - 1
while left < right and nums[left] >= nums[right]:
mid = left + (right - left) / 2
if nums[mid] == nums[left]:
left += 1
elif nums[mid] < nums[left]:
right = mid
else:
left = mid + 1
return nums[left]