Easy
Final Prices With a Special Discount in a Shop — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
class Solution {
public:
vector<int> finalPrices(vector<int>& prices) {
vector<int> stk;
for (int i = 0; i < prices.size(); ++i) {
while (!stk.empty() && prices[stk.back()] >= prices[i]) {
prices[stk.back()] -= prices[i];
stk.pop_back();
}
stk.emplace_back(i);
}
return prices;
}
};