Medium
Extra Characters in a String — Python
Full explanation · Time O(n * l) · Space O(n + t)
# Time: O((n + m) * l), l is max(len(w) for w in dictionary)
# Space: O(n + t)
import collections
# trie, dp
class Solution(object):
def minExtraChar(self, s, dictionary):
"""
:type s: str
:type dictionary: List[str]
:rtype: int
"""
_trie = lambda: collections.defaultdict(_trie)
trie = _trie()
for word in dictionary:
reduce(dict.__getitem__, word, trie).setdefault("_end")
dp = [float("inf")]*(len(s)+1)
dp[0] = 0
for i in xrange(len(s)):
dp[i+1] = min(dp[i+1], dp[i]+1)
curr = trie
for j in xrange(i, len(s)):
if s[j] not in curr:
break
curr = curr[s[j]]
if "_end" in curr:
dp[j+1] = min(dp[j+1], dp[i])
return dp[-1]