Erect the Fence II — Python

# Time:  O(n) on average
# Space: O(n)

import random


# reference: https://en.wikipedia.org/wiki/Smallest-circle_problem
class Solution(object):
    def outerTrees(self, trees):
        """
        :type trees: List[List[int]]
        :rtype: List[float]
        """
        def dist(a, b):
            return ((a[0]-b[0])**2 + (a[1]-b[1])**2)**0.5

        def inside(c, p):
            return dist(c[0], p) < c[1]+EPS

        def circle_center(bx, by, cx, cy):
            B = bx*bx + by*by
            C = cx*cx + cy*cy
            D = bx*cy - by*cx
            return [float(cy*B - by*C)/(2*D),
                    float(bx*C - cx*B)/(2*D)]

        def circle_from_2_points(A, B):
            C = [(A[0]+B[0])/2.0, (A[1]+B[1])/2.0]
            return [C, dist(A, B)/2.0]

        def circle_from_3_points(A, B, C):
            I = circle_center(B[0]-A[0], B[1]-A[1],
                              C[0]-A[0], C[1]-A[1])
            I[0] += A[0]
            I[1] += A[1]
            return [I, dist(I, A)]

        def trivial(boundaries):  # circumscribed circle
            if not boundaries:
                return None
            if len(boundaries) == 1:
                return [boundaries[0], 0.0]
            if len(boundaries) == 2:
                return circle_from_2_points(boundaries[0], boundaries[1])
            return circle_from_3_points(boundaries[0], boundaries[1], boundaries[2])

        def Welzl(points, boundaries, curr):
            if curr == len(points) or len(boundaries) == 3:
                return trivial(boundaries)
            result = Welzl(points, boundaries, curr+1)
            if result is not None and inside(result, points[curr]):
                return result
            boundaries.append(points[curr])
            result = Welzl(points, boundaries, curr+1)
            boundaries.pop()
            return result

        EPS = 1e-5
        random.seed(0)
        random.shuffle(trees)
        result = Welzl(trees, [], 0)
        return result[0][0], result[0][1], result[1]