Medium
Eliminate Maximum Number of Monsters — C++
Full explanation · Time O(nlogn) · Space O(1)
// Time: O(nlogn)
// Space: O(1)
class Solution {
public:
int eliminateMaximum(vector<int>& dist, vector<int>& speed) {
for (int i = 0; i < size(dist); ++i) {
dist[i] = (dist[i] - 1) / speed[i];
}
sort(begin(dist), end(dist));
int result = 0;
for (; result < size(dist) && result <= dist[result]; ++result);
return result;
}
};