Medium
Divisible Game — C++
Full explanation · Time precompute: O(r) runtime: O(nlogx) · Space O(r + n)
// Time: precompute: O(r)
// runtime: O(nlogx + f) = O(nlogx), f = sum of distinct prime factors over all nums (<= 7n)
// Space: O(r + n)
// number theory, kadane's algorithm, prefix sum
vector<int> linear_sieve_of_eratosthenes(int n) { // Time: O(n), Space: O(n)
vector<int> spf(n + 1, -1);
vector<int> primes;
for (int i = 2; i <= n; ++i) {
if (spf[i] == -1) {
spf[i] = i;
primes.emplace_back(i);
}
for (const auto& p : primes) {
if (i * p > n || p > spf[i]) {
break;
}
spf[i * p] = p;
}
}
return spf;
}
const int MAX_NUMS = 1e6;
const auto& SPF = linear_sieve_of_eratosthenes(MAX_NUMS);
class Solution {
public:
int divisibleGame(vector<int>& nums) {
static const int MOD = 1e9 + 7;
vector<int> prefix(size(nums) + 1);
for (int i = 0; i < size(nums); ++i) {
prefix[i + 1] = prefix[i] + nums[i];
}
unordered_map<int, vector<int>> lookup;
for (int i = 0; i < size(nums); ++i) {
int x = nums[i];
while (x != 1) {
const auto& p = SPF[x];
lookup[p].emplace_back(i);
while (x % p == 0) {
x /= p;
}
}
}
int best_diff = -ranges::min(nums), best_k = 2;
for (const auto& [p, idxs] : lookup) {
int total = 0, j = -1;
for (const auto& i : idxs) {
total = max(total - (prefix[(i - 1) + 1] - prefix[j + 1]), 0) + nums[i];
if (total > best_diff) {
best_diff = total;
best_k = p;
} else if (total == best_diff) {
best_k = min(best_k, p);
}
j = i;
}
}
return ((static_cast<int64_t>(best_diff) * best_k) % MOD + MOD) % MOD;
}
};