Easy
Design Compressed String Iterator — Python
Full explanation · Time O(1) · Space O(1)
# Time: O(1)
# Space: O(1)
import re
class StringIterator(object):
def __init__(self, compressedString):
"""
:type compressedString: str
"""
self.__result = re.findall(r"([a-zA-Z])(\d+)", compressedString)
self.__index, self.__num, self.__ch = 0, 0, ' '
def next(self):
"""
:rtype: str
"""
if not self.hasNext():
return ' '
if self.__num == 0:
self.__ch = self.__result[self.__index][0]
self.__num = int(self.__result[self.__index][1])
self.__index += 1
self.__num -= 1
return self.__ch
def hasNext(self):
"""
:rtype: bool
"""
return self.__index != len(self.__result) or self.__num != 0