Medium
Delete Operation for Two Strings — Python
Full explanation · Time O(m * n) · Space O(n)
# Time: O(m * n)
# Space: O(n)
class Solution(object):
def minDistance(self, word1, word2):
"""
:type word1: str
:type word2: str
:rtype: int
"""
m, n = len(word1), len(word2)
dp = [[0] * (n+1) for _ in xrange(2)]
for i in xrange(m):
for j in xrange(n):
dp[(i+1)%2][j+1] = max(dp[i%2][j+1], \
dp[(i+1)%2][j], \
dp[i%2][j] + (word1[i] == word2[j]))
return m + n - 2*dp[m%2][n]