Medium
Delete Nodes And Return Forest — Python
Full explanation · Time O(n) · Space O(h + d)
# Time: O(n)
# Space: O(h + d), d is the number of to_delete
# Definition for a binary tree node.
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution(object):
def delNodes(self, root, to_delete):
"""
:type root: TreeNode
:type to_delete: List[int]
:rtype: List[TreeNode]
"""
def delNodesHelper(to_delete_set, root, is_root, result):
if not root:
return None
is_deleted = root.val in to_delete_set
if is_root and not is_deleted:
result.append(root)
root.left = delNodesHelper(to_delete_set, root.left, is_deleted, result)
root.right = delNodesHelper(to_delete_set, root.right, is_deleted, result)
return None if is_deleted else root
result = []
to_delete_set = set(to_delete)
delNodesHelper(to_delete_set, root, True, result)
return result