Easy
Day of the Year — Python
Full explanation · Time O(1) · Space O(1)
# Time: O(1)
# Space: O(1)
class Solution(object):
def __init__(self):
def dayOfMonth(M):
return (28 if (M == 2) else 31-(M-1)%7%2)
self.__lookup = [0]*12
for M in xrange(1, len(self.__lookup)):
self.__lookup[M] += self.__lookup[M-1]+dayOfMonth(M)
def dayOfYear(self, date):
"""
:type date: str
:rtype: int
"""
Y, M, D = map(int, date.split("-"))
leap = 1 if M > 2 and (((Y % 4 == 0) and (Y % 100 != 0)) or (Y % 400 == 0)) else 0
return self.__lookup[M-1]+D+leap
# Time: O(1)
# Space: O(1)
class Solution2(object):
def dayOfYear(self, date):
"""
:type date: str
:rtype: int
"""
def numberOfDays(Y, M):
leap = 1 if ((Y % 4 == 0) and (Y % 100 != 0)) or (Y % 400 == 0) else 0
return (28+leap if (M == 2) else 31-(M-1)%7%2)
Y, M, result = map(int, date.split("-"))
for i in xrange(1, M):
result += numberOfDays(Y, i)
return result